What Is the Induced EMF in a Moving Conductor?

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SUMMARY

The discussion centers on calculating the induced electromotive force (emf) in a moving conductor within a magnetic field. A metal wire sliding on a horseshoe-shaped loop generates an induced emf of 2 volts while moving at a speed of 16 m/s. The circuit includes a 1Ω resistor and a 6-volt battery, resulting in a current of 2 amps and a voltage drop of 2 volts across the resistor. The mechanical power produced by the motor is calculated to be 4 watts, which equals the total electrical power input, leading to no net power output.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with basic circuit components such as resistors and batteries
  • Knowledge of the relationship between force, current, and magnetic fields
  • Ability to apply equations of motion in the context of electromagnetism
NEXT STEPS
  • Study the principles of Faraday's Law and Lenz's Law in detail
  • Learn about the applications of induced emf in electric generators
  • Explore the concept of power dissipation in resistive circuits
  • Investigate the effects of varying magnetic field strengths on induced emf
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Students and professionals in physics, electrical engineering, and anyone interested in understanding electromagnetic induction and its practical applications in circuits and motors.

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A metal wire slides on a horseshoe-shaped metal loop of width 0.25 m. The loop has negligible resistance, but there is a 1Ω resistor in the circuit as well as a 6 volt battery. There is a uniform magnetic field directed into the plane of the page of magnitude 0.5 T. The slide wire is pushed to the right by the magnetic force. A force of 0.25 N to the left is required to keep it moving a constant speed to the right, i.e. 0.25 N balances the magnetic force.

(a) What is the current in the circuit?
(b) What is the voltage drop across the resistor?
(c) What is the induced emf generated by the moving wire?
(d) With what speed is the wire moving?
(e) What mechanical power (i.e., Fv) does the motor produce?
(f) Subtract from the total electrical power input, the power dissipated in the resistor and compare to the mechanical power.



Relevant equations
F=IlB F=((B^2)(l^2)/R) x v V=IR emf=Blv P=Fv P(dissapated)=(I^2)R


The attempt at a solution
(a) 0.25=I(0.25m)(0.5T) I=2amps
(b) V=(2A)(1Ω) V= 2 volts
(c) 0.25N=((0.5^2)(0.25^2)/(1Ω)) x v
v=16m/s emf=Blv=(0.5T)(0.25m)(16m/s)= 2 volts
(d) v=16m/s
(e) P=(0.25N)(16m/s)= 4 watts
(f) total power input = VI= 2volts x 2 amps = 4 watts
4 watts - 4 watts = 0 watts
0 watts ≠ 4 watts

No idea if I did this right. Please help me! Thanks in advanced.
 
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