How is the Riemann tensor proportinial to the curvature scalar?

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The discussion centers on the relationship between the Riemann tensor and the curvature scalar, particularly in the context of Einstein's field equations. The inquiry suggests that the professor is referring to a proportionality that exists in maximally symmetric spaces. The formula indicated relates the Riemann tensor to the curvature scalar through the metric tensor. Examples such as spheres, de Sitter, and anti-de Sitter spaces can be used to verify this relationship. Understanding this connection is crucial for grasping the geometric implications of curvature in general relativity.
Lyalpha
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My professor asks, "Double check a formula that specifies how Riemann tensor is proportional to a curvature scalar." in our homework.

The closet thing I can find is the relation between the ricci tensor and the curvature scalar in einstein's field equation for empty space.
 
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And by proportinial, I mean proportional.
 
He probably means the relation one has for maximally symmetric spaces, which you can find e.g. in Nakahara. It should be something like

<br /> R_{abcd} \propto R [g_{[a[c}g_{d]b]}]<br />

You can check this for a sphere, deSitter and antideSitter.
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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