How Is the ROC Right of the Rightmost Pole When There's a Pole at -2?

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SUMMARY

The discussion centers on the Region of Convergence (ROC) for a right-sided signal in relation to its poles. Participants agree that the ROC should be defined as Re(s) > -2, given the presence of a pole at -2. The consensus indicates a likely typographical error in the referenced material, which incorrectly states the ROC as Re(s) > -3. This clarification is crucial for accurate analysis in signal processing.

PREREQUISITES
  • Understanding of Laplace Transforms
  • Familiarity with poles and zeros in signal processing
  • Knowledge of right-sided signals
  • Basic concepts of Region of Convergence (ROC)
NEXT STEPS
  • Review the properties of Laplace Transforms and their applications
  • Study the implications of poles and zeros on system stability
  • Explore examples of right-sided signals and their ROCs
  • Investigate common typographical errors in signal processing textbooks
USEFUL FOR

Students and professionals in electrical engineering, particularly those focusing on signal processing and control systems, will benefit from this discussion.

reddvoid
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in this question x(t) is right sided signal
so ROC should be to the right of right most pole
but here they've given ROC is Re(s) >-3
but there is a pole @ -2
attachment.php?attachmentid=39435&stc=1&d=1317394829.jpg

how is this ?
 

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Yes I also think that the ROC should be Re(s)>-2. Looks like the book has a typo.
 
Yes .
I think so
 

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