The specific latent heat of fusion for ice can be calculated using the formula Q = ml, where Q is the total energy supplied, m is the mass of the ice, and L is the latent heat. In this case, with an energy supply of 530 W over 150 seconds for a 0.25 kg sample, the calculation yields a latent heat of 318,000 Joules per kilogram. The units for the specific latent heat of fusion are confirmed to be Joules per kilogram (J/kg).
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swede5670 said:Homework Statement
Determine the specific latent heat of fusion of ice given the amount of time it takes the ice to melt (150 seconds). Energy is supplied to the ice at 530 W. The sample is .25 kg.
Homework Equations
Q= ml
The Attempt at a Solution
(Time * 530W) = .25kg * L
150 seconds * 530W = .25kg * L
(150 * 530)/.25 = 318,000
This seems huge, can anyone help me determine what the units are?