How Is the Square Root of 6 Derived Using the Square Roots of 2 and 3?

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The square root of 6 can be expressed as the product of the square roots of 2 and 3, formulated as √6 = √2 * √3. This relationship highlights the property of square roots that allows for the multiplication of their factors. The discussion confirms the mathematical validity of this expression without delving into further implications or applications. The conversation remains focused on the derivation of √6 specifically through its constituent square roots. Understanding this derivation is fundamental in grasping more complex mathematical concepts.
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Square Root of 6

<math>\sqrt{6}=\frac{sqrt{2}sqrt{3}}<\math>
 
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Instead of <math>, try using [ tex ] (without the spaces)

And yes
\sqrt{6} = \sqrt{2} \sqrt{3}.

What is your point?
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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