A How is the Temperature of Gas in a Cluster Calculated?

[physgeek2033]

TL;DR

I am just trying to parse the following together:

The following link states that: "since kT ~ mpv². A typical velocity dispersion 700 km/s implies T ~ 6 x 107 K from this source alone."

How did they get 6*10^7K ?

When I try this, using mp = 1.67*10^-27 , k =1.38*10^-23 I end up getting 84 as a final answer, nowhere near 6*10^7. Can anyone clarify this? https://pages.astronomy.ua.edu/keel...o the temperature associated with the cluster

 

[Drakkith]

Check your work. Plugging in $\frac{m_p v^2}{k}$ gives me about $6*10^7$.
Remember to convert 700 km/s to m/s.