How Is the Volume of a Spherical Segment Calculated Using Cavalieri's Principle?

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SUMMARY

The volume of a spherical segment can be calculated using Cavalieri's Principle, which states that two solids with the same height and cross-sectional area at every level have the same volume. For a spherical segment with thickness h and sphere radius r, the relevant equations include the volume of a half-sphere, given by \( \frac{2}{3} \pi r^2 \), and the volume of a cone, which is \( \frac{1}{3} \pi r^2 \). The derivation involves understanding the relationship between the spherical segment and the cone formed by the height \( \alpha = r - h \).

PREREQUISITES
  • Cavalieri's Principle
  • Geometry of spheres and cones
  • Volume calculations for solids of revolution
  • Basic calculus concepts related to integration
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  • Study the derivation of the volume of a spherical segment using Cavalieri's Principle
  • Explore the relationship between the volumes of cones and spheres
  • Learn about the application of integration in calculating volumes of solids
  • Investigate examples of solids of revolution in geometry
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Homework Statement



Use Cavalieri's Principle to find the volume of a spherical segment of one base and thinckness h if the radius of the sphere is r.

Homework Equations



http://img395.imageshack.us/img395/2826/sphere1.jpg

Volume of half-sphere: 2/3\pir2
Volume of cone inverse to half-sphere: 1/3 \pir2

The Attempt at a Solution



I've been working this for the last three days and can't see how the answer is derived. The best I've been able to do is work out a cone with height and radius \alpha where \alpha= r-h

But I haven't had any success this way, and question its usefulness.

If need be, I can post what the answer is supposed to be, I'm just interested in how its derived.
 
Last edited by a moderator:
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navybuttons said:

Homework Statement



Use Cavalieri's Principle to find the volume of a spherical segment of one base and thinckness h if the radius of the sphere is r.

Homework Equations



http://img395.imageshack.us/img395/2826/sphere1.jpg

Volume of half-sphere: 2/3\pir2
Volume of cone inverse to half-sphere: 1/3 \pir2

The Attempt at a Solution



I've been working this for the last three days and can't see how the answer is derived. The best I've been able to do is work out a cone with height and radius \alpha where \alpha= r-h

But I haven't had any success this way, and question its usefulness.

If need be, I can post what the answer is supposed to be, I'm just interested in how its derived.

Le Cavalieris principle is about functions in the plane (2d) that are "hightened" into space (3d) by revolving them about the x-axis. A cut half circle would do here.
 
Last edited by a moderator:

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