How Is Torque Calculated for a Bucket on a Cylinder?

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Homework Help Overview

The problem involves calculating the torque produced by a bucket filled with water attached to a rope wound around a cylinder. The scenario includes a bucket with a specified mass and a cylinder with a defined radius, situated at the top of a well.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of force and torque, with one participant checking their approach to the problem. There are considerations about the setup of the cylinder and the forces acting on it, including the definition of torque and its relation to the forces involved.

Discussion Status

The discussion includes attempts to clarify the calculation of torque and the forces at play. Some participants express uncertainty about their calculations and the physical setup, while others provide insights into the definition of torque and its application in this context. There is no explicit consensus, but guidance has been offered regarding the interpretation of the problem.

Contextual Notes

Participants are navigating the definitions and calculations related to torque, with some uncertainty about the physical arrangement of the cylinder and the forces acting on it. The problem is framed within a homework context, which may impose specific constraints on the discussion.

BunsenBurner1
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[SOLVED] torque question

Homework Statement


A bucket filled with water has a mass of 23 kg and is attached to a rope wound around a cylinder with a radius of 0.050 m at the top of a well. What torque does the weight of the water and bucket produce on the cylinder?


Homework Equations


F=ma
g=9.8 m/s
Torque= Force*radius

The Attempt at a Solution


just checking if this is the way to go...
F= 225.4 N
so torque= 11.27?

i just plugged in the numbers but I'm not entirely sure of what's going on in this scenario.
 
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The force of the bucket and water is acting on the cylinder. I'm imagining that the cylinder is placed horizontally and its ends secured to the well.

The torque is defined as the vector product of the force and the distance from pivot that forces an object to rotate. Because of normal forces acting on the cylinder where it is secured, the cylinder is at rotational equilibirum and does not topple over.
 
BunsenBurner1 said:
i just plugged in the numbers but I'm not entirely sure of what's going on in this scenario.

The torque of a force about a point is the product of the perpendicular distance from that point on the line of action of the force and the force. In this case the weight is acting tangentially on the cylinder, via the rope, and the torque of that force about the axis of the cylinder is the weight X radius of cylinder.

You should write the torque as 11.27 Nm.
 
oh i get it now. thanks!
 

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