How is Torque Calculated in a Rotation Lab?

[Yoli123]

Homework Statement

For each meter stick on fulcrum with attached masses (equilibrium/no equilibrium) find torque and rotation

Relevant Equations

equilibrium for rotation

So for the first one on the left is it T= 2g*20=40Nm ? Our professor said it is clockwise I just don't understand how she gets that conclusion.

 

[berkeman]

Homework Statement:: For each meter stick on fulcrum with attached masses (equilibrium/no equilibrium) find torque and rotation
Relevant Equations:: equilibrium for rotation

So for the first one on the left is it T= 2g*20=40Nm ? Our professor said it is clockwise I just don't understand how she gets that conclusion.

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Can you please post a PDF version of the document? It's can be dangerous to open a Word document. You can use PrimoPDF or any other free PDF writer. Thanks.

And what does this mean? "T= 2g*20=40Nm"

g is not a force, and you had a lever arm of 20 meters?

 

[haruspex]

So for the first one on the left is it T= 2g*20=40Nm ? Our professor said it is clockwise I just don't understand how she gets that conclusion.

I couldn't find in the attachment where the units of mass are stated. I assume they are kg. So you have a 2kg mass attached at 20cm from the fulcrum. g is given as 9.8m/s². Paying careful attention to units, what does that give for the torque?
The mass is attached to the right of the fulcrum, so that side should go down. Seems like clockwise to me.