How Is Torque Calculated in This Physics Problem?

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Torque is calculated using the formula T = fxd, where 'f' is the force applied and 'd' is the distance from the pivot point. In this discussion, the torque is influenced by the weight added to either side of the axle, causing counterclockwise or clockwise rotation. The calculated total torque is 980 Nm, assuming the diagram is accurate. There is some confusion regarding the lever arm's angle and its horizontal distance from the axle. Clarifying the original question may help resolve any misunderstandings about torque application points.
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Homework Statement

, [/B]
Please see the attached picture. But I'm trying to do is figure out where this moment would be created and how much torque would be applied based upon this example.

Homework Equations


T = fxd

The Attempt at a Solution

[/B]
I would suspect that any weight added to the left side of the axle would be pushing the system in a counterclockwise fashion. And, conversely, I need weight added on the right side of the axle wood have a tendency to counter that by pushing the axle in a clockwise fashion. I believe the total torque to be:
980 Nm
 

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Pinon1977 said:
I believe the total torque to be:
980 Nm
If your diagram is accurate, yes, but it looks odd that in spite of the lever arm being rotated to some unspecified angle to the horizontal the weight is exactly 1m horizontally from the axle. Maybe you shoukd post the original question exactly as given to you.

Your question about where exactly the torque is applied suggests some misunderstanding. The torque applies at whichever point you chose to calculate it about; in this case, the centre of the axle.
 

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