How Is Torque Generated by Friction on a Rotating Disc Calculated?

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Discussion Overview

The discussion centers on calculating the torque generated by friction on a spinning circular disc resting on a table, with a focus on the role of the coefficient of friction and the integration process involved in the calculation. The scope includes mathematical reasoning and conceptual clarification regarding the forces acting on differential elements of the disc.

Discussion Character

  • Mathematical reasoning, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant inquires about the appropriate definitions of force (F) and radius (r) in the torque equation τ=Fxr for a rotating disc.
  • Another participant suggests using calculus to divide the disc into narrow rings to facilitate the calculation of torque.
  • A participant expresses confusion regarding the friction force on a differential element, questioning whether it should be expressed as μN=μmg or μg dm, and how to determine the bounds for integration.
  • One reply provides a formula for the differential torque as dτ = μg r d m, noting that the limits of integration depend on the definition of dm and suggesting a relationship to volume (dV) to exploit symmetry.
  • It is mentioned that the friction force acts opposite to the velocity vector, and that the friction torque twists in the opposite direction to the angular velocity.

Areas of Agreement / Disagreement

Participants express varying degrees of understanding regarding the calculation process, with some confusion remaining about the integration bounds and the definition of differential mass elements. No consensus is reached on the specific approach to take.

Contextual Notes

The discussion highlights limitations related to the assumptions made about the friction force and the integration process, as well as the dependence on the definitions used for differential mass elements.

johnysmithers
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If I have a spinning circular disc of uniform density, how would I find the torque generated by friction, if the disc is lying flat against a table with coefficient of friction μ? τ=Fxr, but what is F, and what is r in this case?
 
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Welcome to PF;

You use calculus ... divide the disk into narrow rings.
 
Thank you Mr. Bridge, for your reply. I am still confused however, as towhat the force on a differential element would be. The friction force would be μ N=μ m g(or would it be μ g dm?) The friction force would always act perpendicular to position, so torque would be upward with magnitude equal to the product of the distance from the center and the force. However, I am not sure what I would be integrating with respect to, and I am also unsure as to what the bounds on the integration would be. Please clarify? Thank you in advance.
 
That would be:
##d\tau = \mu g r \text{d}m##

The limits of the integration depend on how you define dm ...
hint: relate dm to dV (volume) and exploit the symmetry.

Friction force always acts opposite to the velocity vector.
Friction torque always twists the opposite way to the angular velocity.
 

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