How is Vmax Derived as 2πfA from Given Formulae?

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SUMMARY

The maximum speed (Vmax) of a mass on a spring is derived as 2πfA, where f represents frequency and A denotes amplitude. This derivation utilizes the equations of motion for a spring, specifically the relationships ma = -(k)(x) and f = 1/(2π)√(k/m). By squaring the expression for Vmax and substituting the relevant terms, one can demonstrate that Vmax is directly proportional to both frequency and amplitude, confirming the formula's validity.

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  • Understanding of harmonic motion and spring dynamics
  • Familiarity with the concepts of frequency and amplitude
  • Knowledge of Newton's second law of motion
  • Basic algebra for manipulating equations
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Physics students, mechanical engineers, and anyone studying oscillatory motion and spring dynamics will benefit from this discussion.

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Given the following formulaes prove that maximum speed (Vmax) of a mass on a spring is given by 2(pi)(frequency)(Amplitude)

(constant k) A^2 = mv^2 + (constant k) x^2 ma = -(constant k)(x)

f = 1/2(pi) sqrt (a/-x) and f = 1/2(pi) sqrt (constant k/m)

i just don't see how i can make it work... any suggestions?
 
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quickslant said:
Given the following formulaes prove that maximum speed (Vmax) of a mass on a spring is given by 2(pi)(frequency)(Amplitude)

(constant k) A^2 = mv^2 + (constant k) x^2

ma = -(constant k)(x)

f = 1/2(pi) sqrt (a/-x)

f = 1/2(pi) sqrt (constant k/m)

i just don't see how i can make it work... any suggestions?

You need to use carriage returns to put equations on separate lines. Extra spaces do not get included in posts.

Start with 2(pi)(frequency)(Amplitude) and square it. Then make substitions.
 
Last edited:
What happens to the amplitude when the velocity is at its maximum?
 

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