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I think it can be shown that there is a length beyond which it would break, without having to resort to reductio ad absurdam, with its accompanying problems, per my previous post.phinds said:if it were just but if it were just hanging in space on both ends it would not break. Expansion would not affect it because it would be internally connected by forces that are MUCH stronger than dark energy.
Let F be the breaking strain of the wire, and the wire's mass be w kg/m. The impact of the cosmological constant is that there is some distance D such that l>D\Rightarrow \frac{d^2{l}}{dt^2}>\frac{F}{w} where l is the distance between two free-falling bodies.
Say the wire is longer than 2(D+1) metres and consider the one-metre length at either end. Each is being accelerated by \Lambda away from the centre of the wire with acceleration greater than \frac{F}{w} and since it has mass w that imparts a force of F outwards along the wire. These two opposite forces of F are sufficient to break the wire.
(I think I made the wire twice as long as it needs to be to break, but never mind.)
The length D is enormously more than it would need to be to break the wire if it were attached to a planet at either end, because the force from 'dark energy' is proportional to the mass at either end of the wire. However, there is some length at which an unattached straight wire would break.
Ah: I see that Nugatory has already made this point a few posts earlier. I had only read the first page of this thread.