A satellite at an altitude of 325 km orbits Earth with a specific orbital period determined by gravitational forces. The relevant equations include the net force equation, expressed as 4π²r/T², and the gravitational force equation, Fg = Gm1m2/r². The radius of Earth is 6.38 x 10^6 meters, and its mass is 5.98 x 10^24 kg. Correctly applying these equations will yield the orbital period.
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This is not correct. Check the dimensions. This has the dimensions of distance/time^2.Klee91 said:Homework Statement
A satellite orbits Earth at an altitude of 325 km above the planet's surface. what is the oribital period? (radius of Earth =6.38 x 10 ^ 6 meters, mass of Earth = 5.98 x 10^24 kg)Homework Equations
Net force = 4 pi^2r/T^2