How Long Does It Take a Feather to Fall 1.4 Meters on the Moon?

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Homework Help Overview

The discussion revolves around a physics problem concerning the time it takes for a feather to fall 1.4 meters on the Moon, where the acceleration due to gravity is 1.67 m/s². Participants are exploring the relevant equations of motion to determine the time of fall.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various equations that relate distance, acceleration, time, and initial velocity. There is uncertainty about which equation to apply and how to manipulate it correctly to find the time.

Discussion Status

Some participants have attempted different equations but have encountered difficulties in obtaining the correct answer. One participant claims to have found the correct answer, though the details of this resolution are not shared.

Contextual Notes

There is mention of initial and final velocities being zero, and participants are working within the constraints of the problem without additional information or context about the feather's behavior in a vacuum.

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A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2 Determine the time for the feather to fall to the surface of the moon.

So, I wrote my given:
d=1.4 m
a= 1.67 m/s2
both initial and final velocity= 0

I know I am looking for time, but I have no idea what equation to use. I tried:
vf= vi+at , but I didn't get the right answer. The answer should be 1.29 s.
Any help would be much appreciated, please and thank you!:)
 
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Well what equation involves d,a,t and u (initial velocity)?
 
This does: d=vi+1/2*at2
but I didn't get the right answer with that either, I got .75:(
 
I got the right answer now.:)
 

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