How long does it take for a plane to come to a stop in an emergency landing?

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SUMMARY

The emergency landing scenario involves a light plane weighing 2,500 lb landing at a speed of 120 ft/s on a short runway. The plane's stopping time is calculated based on the forces acting on it, including a frictional force of 3,200 lb*ft/s² from a sandbag and an additional retarding force of 300 lb from the brakes. The resulting differential equation yields a stopping time of 23 seconds. The discussion also highlights a potential unit error in the viscous force calculation.

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  • Understanding of Newton's second law (F = ma)
  • Knowledge of frictional force calculations (f = mu * m * g)
  • Familiarity with differential equations
  • Basic concepts of forces in motion
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  • Review the principles of Newtonian mechanics
  • Study the application of differential equations in physics
  • Learn about friction coefficients and their impact on motion
  • Explore advanced topics in dynamics, such as viscous damping
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tylerc1991
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Homework Statement



This is a problem from K & K, but I changed it very slightly.

A light plane weighing 2,500 lb makes an emergency landing on a short runway. With its engine off, it lands on the runway at 120 ft/s. A hook on the plane snags a cable attached to a 250 lb sandbag and drags the sandbag along. If the coefficient of friction between the sandbag and the runway is 0.4, and if the plane's brakes give an additional retarding force of 300 lb, how long does it take for the plane to come to a stop?

Homework Equations



f = force of friction = mu * m * g

viscous force = -C * v, where C is some constant

F = ma

The Attempt at a Solution



Let's say that the positive x is positive direction. The acceleration of the sandbag and the plane is the same since they are connected by a cable. The force of friction is given by

f = mu * m_sandbag * g = - 3200 lb*ft/s^2

And the additional retarding force from the brakes is

f_v = - 300 v(t) lb*ft/s

So we have

- 3200 - 300 v(t) = m_total * a

or

-3200 - 300 v(t) = 2750 * dv/dt.

After I solved this differential equation and set v(t) = 0, I found that the time required for the plane to come to a stop is t = 23 seconds.

Does this look right? Thank you!
 
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I think f_v has the wrong units.
 

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