# What's the Force Exerted? and how long it takes to stop

## Homework Statement

Johnny, of mass 65 kg, and Lucy, of mass 45 kg, are facing each other on roller blades. The coefficient of kinetic friction between the roller blades and concrete surface is 0.20. When Johnny pushes Lucy from rest he applies a force for 1.0 s. Lucy then slows down to a stop in another 8.0 s. Calculate:
a. The applied force exerted by Johnny on Lucy. [790 N]
b. How long it takes Johnny to come to rest. [5.1s]

## Homework Equations

F = ma
Vf = Vi + at
x(t) = Vi * t + 0.5*a*t^2

## The Attempt at a Solution

Fk = (miu)*mass*9.81 = (0.2) (45Kg) (9.81 m/s^2) = 88.3 N
Vf = Vi + at = 0 + a(8s)

haruspex
Homework Helper
Gold Member
Ouch. This is a very badly worded question. The coefficient of friction between the roller blades and the concrete has nothing to do with it. The roller blades will roll - that is what they are designed to do. The friction will do no work and therefore not slow Lucy at all.
What the question setter means (I hope) is rolling resistance. This is typically a result of friction at the axle of the wheel and/or deformation of the wheel as the load on it changes.
Putting that aside, you have calculated the force that will take Lucy from maximum speed (her speed when the push ends) to rest in 8 seconds. Now you want the force that goes the opposite way - from rest to maximum speed - in 1 second. Any thoughts?
You quote an equation involving an acceleration and two speeds. How can you connect that with forces?

• Chestermiller
I tried connecting the two forces Fapp = - F john on lucy but I still need acceleration, which I can't figure out because there is no distance.

haruspex