How Do You Solve This Pulley and Friction Problem?

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SUMMARY

The discussion focuses on solving a pulley and friction problem involving two blocks, A and B, with weights of 100 lbs and 50 lbs respectively. The coefficient of kinetic friction is given as µk = 0.2. The correct acceleration of block A is determined to be 1.29 ft/s², and the distance it slides before stopping is 9.70 feet. The initial calculations by the user were incorrect due to a misunderstanding of how to calculate the normal force, which is essential for determining the frictional force.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of frictional force calculations (F(friction) = µ*N)
  • Familiarity with kinematic equations (V² = V₀² + 2ad)
  • Basic concepts of pulley systems and tension forces
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  • Study how to calculate normal forces in inclined plane problems
  • Learn about tension forces in pulley systems
  • Explore advanced kinematic equations for motion under friction
  • Review examples of multi-body dynamics in mechanics
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Students studying physics, particularly those focused on mechanics, as well as educators looking for problem-solving strategies in pulley and friction scenarios.

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Homework Statement


At the instant shown the 100-lb block A is moving down the plane at 5 ft/s while being attached to the 50-lb block B. If the coefficient of friction is µk = 0.2, determine the acceleration of A and the distance A slides before it stops. Neglect the mass of the pulleys and cables.
http://0pcode.ath.cx/photo.jpg
The picture was taken with my phone, so the triangle under A is kinda hard to see. Its hypoteneuse is 5, the vertical leg is 3, and the horizontal leg is 4.


Homework Equations


F = ma
m = W/g (slug)
F(friction) = µ*N
V^{2} = V^{2}_{0} + 2ad

The Attempt at a Solution


I tried finding the frictional force of block A first, which I calculated to be 16-lb. I then found the tension force in the rope at A, which I calculated to be 12.5-lb. I then took those two values and added them together, and got an acceleration value of 9.12ft/s^2. And I found the distance the block slides to be 1.37 feet.
The answers are supposed to be 1.29ft/s^2, and 9.70 feet. I don't know where I went wrong, any help would be appreciated :) Thanks.
 
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Hi AcecA! :smile:
AcecA said:
… I tried finding the frictional force of block A first, which I calculated to be 16-lb. I then found the tension force in the rope at A …

Nooo … to find the friction force, you first need to find the normal force, and that will depend on the acceleration.

In this sort of problem, everything depends on everything else :rolleyes:

you can't "start at one end and work your way across" (the way we do in most mechanics problems :wink:)

Hint: call the tensions T1 and T2, and the distance along the slope x, and then use good ol' Newton's second law twice, once for A and once for B. :smile:
 

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