- #1

- 166

- 2

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Tyrion101
- Start date

- #1

- 166

- 2

- #2

- 16,918

- 7,885

- #3

collinsmark

Homework Helper

Gold Member

- 2,939

- 1,389

If the problem involves right triangles (utilizing the Pythagorean therem, *c*^{2} = *a*^{2} + *b*^{2}) then it ends up pretty easy if the triangles are 3-4-5 triangles (5^{2} = 3^{2} + 4^{2}).

You can also scale the 3, 4 and 5 by any constant and it still works out. For example, let's multiply them all by 123.

*c*^{2} = 369^{2} + 492^{2}.

Solve for*c*.

You can also scale the 3, 4 and 5 by any constant and it still works out. For example, let's multiply them all by 123.

Solve for

Last edited:

- #4

AlephZero

Science Advisor

Homework Helper

- 6,994

- 293

- #5

lisab

Staff Emeritus

Science Advisor

Gold Member

- 1,887

- 617

Not very hard for those who can easily solve them forwards and back. But for someone first learning, it's an interesting observation. I wonder how many students are shocked the first time they get an answer that has a digits after the decimal, and realize it's a correct answer!

Share:

- Replies
- 5

- Views
- 1K