How Long Should Radiation Therapy Last After Two Years to Match Initial Dosage?

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SUMMARY

The discussion centers on calculating the required duration of radiation therapy after two years to match the initial dosage received by a cancer patient. Given a radioactive source with a half-life of 2 years, the patient initially receives 10 minutes of irradiation, equating to 100% dosage. After two years, the radioactivity of the source decreases to 50%, necessitating a total of 20 minutes of irradiation (two sessions of 10 minutes) to achieve the same cumulative dosage of 100% as initially received.

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Homework Statement


a patient who is undergoing cancer theraphy is given 10 mins of irradiation from a radioactive source that has half life = 2 years. If the same source is to be used for same treatment 2 years later , how long should the patient should be irradiated?

the ans is 20 mins .. can someoene teach me how to do this?

Homework Equations

The Attempt at a Solution


i was told that:
at time = 0 (ie. Now) the patient undergoes 10 mins of irradiation. Let's say the amount of radioactivity of the source now is at 100%

We are told that it's half life is 2 years which means in 2 years the radioactivity of the source is at 50%.

So suppose it is 2 years later
if the patient's therapy lasts 10 min - he gets 50% dosage.
if the patients therapy goes another 10 min - he gets another 50% dosage
So a total of 20 min of therapy results in (50% + 50% = 100% same dosage as he received 2 years earlier)

but why if the patient's therapy lasts 10 min - he gets 50% dosage. ??[/B]
 
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You're doing the right thing. Dosage is proportional to the time and to the radioactivity of the source: dosage is something like the amount of radioactive decays, so activity (decays/time) times time.
 
why if the patient's therapy lasts 10 min - he gets 50% dosage. ??
Instead of the patient, imagine there is a Geiger counter, and explain what it would record.
 

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