Find area under a decay curve if half life is increasing

In summary, the area under a decay curve can be found using the formula for exponential decay and adjusting the decay constant for increasing half-life. The decay constant is inversely proportional to the half-life, and the area cannot be calculated without knowing the half-life. An increasing half-life means a slower rate of decay, and the area under a decay curve can be used to determine the half-life of a substance by solving for time and using the formula for half-life.
  • #1
BillyT
63
4
Area under decay curve exp(-0.6969t/h) where t is the time (with t=0 initially) and h is a constant "half life" is analytically integrable, but what if the half life is increasing with time? I. e. if h(t) = H + at.
(Note exp(-0.6969) is not exactly 0.5 but close and easy to remember.)
This problem arises when trying to evaluate the total blocking of a "puff" green house gas, like methane CH4 released at t = 0. CH4 in the air is mainly destroyed by the OH- radical. OH- production rate is limited by the flux of harsh solar UV. For at least the 800,000 years this production rate was greater than the release of CH4, but that is no longer true.
http://www.epa.gov/climatechange/images/indicator_figures/ghg-concentrations-figure2-2014.png

For the last few decades, the CH4 release rate has been faster than the OH- is formed, as seen above. I.e. now the CH4 is destroying the OH- so the half life of CH4 is increasing. The CH4 half life was 9.6 years in 2003 and 12.4 in 2013*.

Lets assume half life is given by: h(t) = 12.6(1+ 0.3t) with t in years and t = 0 on 1/1/2015.

Can you integrate how many "puff years" exist for some specific period of years?

As CO2 has a half life of more than 1000 years, other green house gas puffs are usually compare to it. I.e. How much more global warming a puff of CH4 will make compared to an equal mass of CO2 released at the same time, during the next X years. Here are some results:

t = 1/365: 120 times more than the CO2 did.
t = 10: 104 times more
t = 20: 83.8 times more
t = 50: 48.4 times more
t = 100: 28.5 times more
t = 500: 8.1 times more

So little of the puff's CH4 is left after 1000 years probably is less than one as about half of a fossil fuel released puff would still exist. Some of the comparison puff of CO2 molecules may have spent many decades absorbed in the ocean, before re-entering the air; but not all will be part of shells lying on the bottom, etc.

If you can give results for some of the same year with above h(t) I thank you. Please also give integral for h = 12.4 as that was assumed for data above. With that and the above data I can convert your results into a new table for the years you give both.

* Some report it as 12.6 in 2013.
 
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  • #2
BillyT said:
Area under decay curve exp(-0.6969t/h) where t is the time (with t=0 initially) and h is a constant "half life" is analytically integrable, but what if the half life is increasing with time? I. e. if h(t) = H + at.
(Note exp(-0.6969) is not exactly 0.5 but close and easy to rmember.)
This problem arises when trying to evaluate the total blocking of a "puff" green house gas, like methane CH4 released at t = 0. CH4 in the air is mainly destroyed by the OH- radical. OH- production rate is limited by the flux of harsh solar UV. For at least the 800,000 years this production rate was greater than the release of CH4, but that is no longer true.
http://www.epa.gov/climatechange/images/indicator_figures/ghg-concentrations-figure2-2014.png

For the last few decades, the CH4 release rate has been faster than the OH- is formed, as seen above. I.e. now the CH4 is destroying the OH- so the half life of CH4 is increasing. The CH4 half life was 9.6 years in 2003 and 12.4 in 2013*.

Lets assume half life is given by: h(t) = 12.6(1+ 0.3t) with t in years and t = 0 on 1/1/2015.

Can you integrate how many "puff years" exist for some specific period of years?

As CO2 has a half life of more than 1000 years, other green house gas puffs are usually compare to it. I.e. How much more global warming a puff of CH4 will make compared to an equal mass of CO2 released at the same time, during the next X years. Here are some results:

t = 1/365: 120 times more than the CO2 did.
t = 10: 104 times more
t = 20: 83.8 times more
t = 50: 48.4 times more
t = 100: 28.5 times more
t = 500: 8.1 times more

So little of the puff's CH4 is left after 1000 years probably is less than one as about half of a fossil fuel released puff would still exist. Some of the comparison puff of CO2 molecules may have spent many decades absorbed in the ocean, before re-entering the air; but not all will be part of shells lying on the bottom, etc.

If you can give results for some of the same year with above h(t) I thank you. Please also give integral for h = 12.4 as that was assumed for data above. With that and the above data I can convert your results into a new table for the years you give both.

* Some report it as 12.6 in 2013.

Areas under the graph of the function
[tex] f(t) = \exp\left(-0.6969\frac{t}{h(t)} \right)[/tex]
with a known function ##h(t)##, can be handled easily by numerical methods, even if they cannot be done "analytically" in closed form.

In your specific case ##h(t) = H + at## the integral ##A_T = \int_0^T f(t) \, dt## can be done, but it involves non-elementary "Exponential integrals", or "Incomplete Gamma functions". If you had numerical values for ##H,a##, it would be easy enough to just evaluate ##A_T## for various values of ##T##. Then you could try to fit a convenient function to the numerical results.
 
  • #3
much
Ray Vickson said:
Areas under the graph of the function
[tex] f(t) = \exp\left(-0.6969\frac{t}{h(t)} \right)[/tex]
with a known function ##h(t)##, can be handled easily by numerical methods, even if they cannot be done "analytically" in closed form.

In your specific case ##h(t) = H + at## the integral ##A_T = \int_0^T f(t) \, dt## can be done, but it involves non-elementary "Exponential integrals", or "Incomplete Gamma functions". If you had numerical values for ##H,a##, it would be easy enough to just evaluate ##A_T## for various values of ##T##. Then you could try to fit a convenient function to the numerical results.
Thanks. I have never done any numerical integrations, so if you or some one who has would do the my h(t) for: 10, 20 & 50 years plus give them for the constant 12.4 year half life, that would be much appreciated. What I really want to know is how much greater compared to CO2 the near future effect of CH4 now being released is going to be.

I will use your 12.4 half life year values to get from the tabulated data how much CO2 remains X years after a puff is released. There are three different significant mechanisms for CO2 removal so calculation of how much CO2 remains X years after a puff is released is more complex than for CH4 by a factor of three, at least.
 
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1. How do you find the area under a decay curve if the half-life of the substance is increasing?

The area under a decay curve can be found by using the integral calculus formula for exponential decay, which is A = Ao * e^(-kt), where A is the final amount, Ao is the initial amount, e is the base of natural logarithm, k is the decay constant, and t is the time. To account for the increasing half-life, the decay constant (k) needs to be adjusted accordingly.

2. What is the relationship between half-life and decay constant?

The decay constant (k) is inversely proportional to the half-life of a substance. This means that as the half-life increases, the decay constant decreases and vice versa.

3. Can the area under a decay curve be calculated without knowing the half-life?

No, the half-life is a crucial factor in calculating the area under a decay curve. Without knowing the half-life, it is not possible to determine the decay constant and therefore, the area cannot be accurately calculated.

4. How does an increasing half-life affect the rate of decay?

An increasing half-life means that the substance is decaying at a slower rate. This is because the longer the half-life, the less frequent the decay events are and therefore, the slower the rate of decay becomes.

5. Can the area under a decay curve be used to determine the half-life of a substance?

Yes, the area under a decay curve can be used to determine the half-life of a substance by using the formula for exponential decay (A = Ao * e^(-kt)) and solving for t (time). Once t is known, the half-life can be calculated using the formula for half-life (t1/2 = ln(2)/k).

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