How Long to Reach the Top Walking on a Moving Escalator?

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Homework Help Overview

The problem involves calculating the time it takes for a person to reach the top of a moving escalator, given the escalator's length and the person's walking speed relative to the escalator. The context includes concepts of relative motion and velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the escalator's velocity and the implications of relative motion. Questions arise about whether to add the velocities of the person and the escalator and the nature of relative motion.

Discussion Status

Participants are engaging in a dialogue about the concepts of relative motion and how they apply to the problem. Some guidance has been offered regarding the interpretation of walking speed relative to the escalator, and there is an exploration of the implications of relative motion.

Contextual Notes

There is an ongoing discussion about the assumptions related to relative motion, including the idea that one reference frame may be stationary while another is in motion.

optoracko
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Homework Statement


An escalator is 20.0m long. If a person stands on the escalator, it takes 50.0s to ride from bottom to the top.

a) if a person walks up the moving escalator with a speed of 0.500 m/s relative to the escalator how long does it take for the person to get to the top.

Homework Equations



V = d / t

The Attempt at a Solution



I'm not understanding relative motion too well. I begin by calculating the velocity of the escalator which is 0.400 m/s. Since the person is walking up with a speed of 0.500 m/s in relation to the escalator, does that mean that if the escalator was not there, he'd be walking at 0.500 m/s? Why would I not add the two velocities (.4 + .5) and isolate for the time?
 
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optoracko said:
I begin by calculating the velocity of the escalator which is 0.400 m/s.
Correct.
Since the person is walking up with a speed of 0.500 m/s in relation to the escalator, does that mean that if the escalator was not there, he'd be walking at 0.500 m/s?
It is better to think of this way: It means that if the escalator were not moving, he'd be walking at 0.500 m/s.
Why would I not add the two velocities (.4 + .5) and isolate for the time?
Why do you think you should not do that?
 
Not quite sure. I guess I thought that if it was moving relative, it would mean that it moves that speed and the speed of the elevator. Blech.

Would that mean that anything with relative motion requires something to be stationary, such as in this question?
 
optoracko said:
Would that mean that anything with relative motion requires something to be stationary, such as in this question?
All motion is relative. You may think that you are at rest sitting in front of your computer reading this message, but
relative to the center of the Earth you are moving at about 1,000 miles an hour
relative to the Sun you are moving much faster
relative to a galaxy far far away much much faster.

Get the picture?
 
Yeah, makes sense now. Thanks!
 

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