- #1

tomas krchnak

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## Homework Statement

There is a escalator and 2 persons move up it. A takes 50 steps and B takes 75 steps while the escalator is moving up. Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps, find the no. of steps in the escalator that is possible to see while it is staionary.?

## Homework Equations

## The Attempt at a Solution

v is the speed of persons (A=1v, B=3v)

x is the number of stairs

y is the speed of escalator

so:

50/v=(x-50)/y

75/3v=(x-75)/y

I make from that:

(50y/v)+50=x

(25y/v)+75=x

and then i remove fractions and have system of equations

50y+50v=xv

25y+75v=xv *(-2) equivalent adjustment

50y+50v=xv

-50y-150v=-2xv

-100v=-xv

-100=-x

x=100

Now I got the number of steps so if I do 100/2=50 is the number of steps we can see if it is stationary.

I just want to ask if is everything right.

And.. I´m not good in english so there are many mistakes in it, so sorry