How Long Will it Take to Heat Water Using a Solar Heater?

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SUMMARY

The discussion centers on calculating the time required to heat 150 kg of water by 30 K using a solar heater with an area of 4.0 m² and a solar radiation intensity of 6000 W/m². The calculation reveals that with a solar panel efficiency of 60%, the energy output is 14,400 W, leading to a heating time of approximately 1312.5 seconds, or about 22 minutes. However, discrepancies arise as the answer sheet suggests a time of 3.6 hours, indicating a potential error in the provided data or a typo in the answer sheet.

PREREQUISITES
  • Understanding of the specific heat capacity formula: E=mcΔT
  • Knowledge of solar panel efficiency calculations
  • Familiarity with energy units (Joules and Watts)
  • Basic principles of solar radiation intensity
NEXT STEPS
  • Research the Solar Constant and its implications for solar energy calculations
  • Explore the effects of solar panel efficiency on heating calculations
  • Investigate common errors in energy calculation problems
  • Learn about the impact of reflectors and additional equipment on solar panel performance
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Students studying thermodynamics, engineers working with solar energy systems, and anyone involved in renewable energy calculations.

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Homework Statement



A solar heater is used to warm 150 kg of water by 30 K. The intensity of solar radiation is 6000 Wm-2 and the area of the panels is 4.0 m2. The specific heat capacity of the water is 4.2 * 103 J/kg/K. Estimate the time this will take, assuming a solar panel efficiency of 60%.

Homework Equations



E=mcΔT

The Attempt at a Solution



Since there are 4 metres squared of solar panel and an efficiency of 60%:

6000 x 0.6 x 4 = 14400 W

The amount of energy needed to heat the water is:

E = mcΔT = 150 x 4.2 x 10^3 x 30 = 1.89 x 10^7 J

Therefore the time it will take is (1.89 x 10^7 J) / 14400 W = 1312.5 s = about 22 minutes.

In the answer sheet it says 3.6 hours, so I'm not sure where I went wrong.

Any help is appreciated!
 
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The given value for solar radiation looks rather high. The Solar Constant is only between 1300 and 1400 W/m2 at the top of the Earth's atmosphere. Perhaps there are unmentioned reflectors to gather more sunlight on the panels?

Otherwise, your calculation appears to be correct for the data given.

Perhaps the answer sheet has a typo (misplaced decimal point in the result). 1312 seconds is about 0.36 hours.
 
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Ok, thanks!
 

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