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**1. I'm trying to work out how much energy is used in heating 2 cubic metres of water per day from 23C to 65C. Basically trying to put a water purifier in Malawi and run it off solar panels. It currently uses 1.3kWh to run the machine but the initial stage involves pre heating water. In Malawi this wont be needed so I'm trying to work out how much less energy the machine will need to run.**

**2. I understand that you need 1 calorie to heat 1 ml of water 1C.**

**3. Heating the water a total of 42C.**

2 cubic meters of water is 2,000,000 ml.

Therefore the machine uses 84,000,000 calories to heat the water, or so I think.

If I use a calorie to kilowatt/hour as 1.163x10-6.

84,000,000 x 1.163x10-6 = 97.7kWh

This is obviously wrong and I'm unsure where, initially thinking maybe because the machine doesn't heat the water all at once as does it gradually over the course of 24 hours?

Any help would be appreciated. I understand this is probably silly on my part but its been a long time since I done physics.

Thanks

2 cubic meters of water is 2,000,000 ml.

Therefore the machine uses 84,000,000 calories to heat the water, or so I think.

If I use a calorie to kilowatt/hour as 1.163x10-6.

84,000,000 x 1.163x10-6 = 97.7kWh

This is obviously wrong and I'm unsure where, initially thinking maybe because the machine doesn't heat the water all at once as does it gradually over the course of 24 hours?

Any help would be appreciated. I understand this is probably silly on my part but its been a long time since I done physics.

Thanks