How Many Electrons Are Equivalent to a +5 nC Charge?

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The discussion centers on calculating the number of electrons equivalent to a +5 nC charge. The correct calculation involves dividing the charge (5 nC) by the elementary charge (e = 1.60 x 10-19 C), resulting in approximately 3.13 x 1010 electrons. A common error noted is the incorrect division of e by the charge, leading to an erroneous result. The importance of unit cancellation in calculations is emphasized to avoid mistakes.

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Ok, for some reason, I'm getting the wrong answer. It's asking for how many electrons were removed from an object that has gained a +5nC charge. Here's my setup.

(1.60x10^(-19)) / ( 5*10^(-9))
I'm getting 3.2*10^(-11)
yet book says the answer is actually 3.13*10^(-10)

wtf?
 
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Well both the book and you are wrong.

If you want wow many electrons are in 5nC, the correct division is 5nC/e. You did e/5nC. The book only has a sign error in the exponent.

You should have gotten a clue that the book answer was wrong, as 3.13*10^(-10) is less than 1 electron and it is a law of nature that you can only mova around charges in amounts multiple of e (until we find how to separate quarks from hadrons that is).
 
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Look at your units. Make sure they cancel, as shown below.

5\,\textrm{nC} \cdot \frac{1 \,\textrm{electron}}{1.6 \cdot 10^{-19} \,\textrm{C}} = x \, \textrm{electrons}

- Warren
 

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