How Many Elements Are in the Semigroup X^X?

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The semigroup X^X, where X is a finite set with n elements, contains exactly n^n elements. This conclusion arises from the fact that X^X is isomorphic to the set of functions from X to X. The notation X^X represents the set of all functions mapping elements of X to itself, confirming that the number of such functions is indeed n^n. This understanding clarifies the relationship between semigroups and function sets in abstract algebra.

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(Moderator's note: thread moved from "Linear & Abstract Algebra")

problem # 12).

Suppose X is a finite set with n elements. Show that the semigroup X^x has n^n elements.

I'm confused. Isn't semigroup a set of functions? So when it says n elements, it actually means n functions? Also what is X^x defined as?
 
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yaganon said:
problem # 12).

Suppose X is a finite set with n elements. Show that the semigroup X^x has n^n elements.

I'm confused. Isn't semigroup a set of functions? So when it says n elements, it actually means n functions? Also what is X^x defined as?

Well, if this semigroup is isomorphic to the set of functions from X to X, then n^n is clearly the right number. I looked at the semigroup page on Wikipedia and couldn't find that notation, though. Can't find it in your textbook?
 

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