How many grams of cold water necessary to lower temperature in container

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SUMMARY

The discussion focuses on calculating the amount of cold water needed to lower the temperature of a warmer water sample. The relevant equation is q = c * m * ΔT, where ΔT represents the temperature change. To achieve a final temperature of 50 degrees Celsius, the heat lost by 100 grams of 80-degree Celsius water must equal the heat gained by the unknown mass of 20-degree Celsius water. The principle of conservation of energy dictates that the heat lost by the warmer water is equal to the heat gained by the cooler water.

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Paulo Serrano
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Homework Statement


How many grams of 20 degree C water do I need to add to 100 grams of 80 degree C of water to get the final temperature down to 50 degrees C?


Homework Equations


I'm sure it's a pretty simple equation, but I don't know it. (I'm studying a lot of different things at once and am not in school)


The Attempt at a Solution


Not sure.

Thanks :)
 
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First you need to know the equation for energy, which is q=c*m*deltaT, where deltaT is T(final)-T(initial). You also know that q of the 20 degree water equals the negative of the 80 degree water. Given this, you should be able to solve for grams of 20 degree water.
 
q is heat energy, correct? Why is one the negative of the other?
 
One is negative of the other because the heat that leaves the 80 degree water is added to the 20 degree water.
 

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