How many helium balloons does it take to lift a person?

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SUMMARY

To determine how many helium balloons are required to lift a person weighing 76 kg, one must apply the principle of buoyancy. The buoyant force (FB) must equal the combined weight of the person (M) and the weight of the helium in the balloons (m). The equation ρHeV = M + ρairV is crucial, where ρHe is the density of helium, ρair is the density of air, and V is the volume of helium. The confusion arises from the correct identification of the buoyant force, which is indeed due to the surrounding air, not the helium itself.

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Homework Statement



How many helium-filled balloons would it take to lift a person? Assume the person has a mass of 76 kg and that each helium-filled balloon is spherical with a diameter of 33 cm.

Homework Equations



P = P0 + ρgV

The Attempt at a Solution



I really don't know why this is confusing me, since it seems pretty straight forward. But, I know that the buoyant force has to be equal to at least the mass of the person (M) + the mass of the helium in all the balloons (m)

which means that FB = Mg + mg

and the buoyant force is due to the helium, so, in order for the person to be lifted,

ρHegV = Mg + mg

so ρHeV = M + m

which is

ρHeVHe = M + ρairVHe

right?

So then M/(ρHe - ρair) = V

but this would be negative...What I am doing wrong?

(I don't need help with the last part which is finding the number of balloons)

thanks!
 
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Wait, I have the density of the air and the helium switched, right? The buoyant force is due to the air and not the helium? Because the air is the fluid that it is in?

This is probably an easy question, but I'm pretty sleep deprived haha
 
pinkerpikachu said:
Wait, I have the density of the air and the helium switched, right? The buoyant force is due to the air and not the helium? Because the air is the fluid that it is in?

Yes, exactly...

ehild
 

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