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How many hydraulic rams do I need to prevent wall collapsing ?

  1. Jan 12, 2013 #1
    1. The problem statement, all variables and given/known data

    rectangle wall with 3m height, 20 length, 6.0m width.
    Rectangle filled with water.



    3. The attempt at a solution


    I've calculated the force acting on the wall to be: 1766 KN

    I have a hydraulic ram exerting 5 tonnes of pressure.

    How many do I need ?

    2. Relevant equations


    F=P.A
     
  2. jcsd
  3. Jan 12, 2013 #2

    rude man

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    Gold Member

    Average pressure = ρgd, d = 3m, g = 9.81 m-s^(-2), ρ = 1e3 kg/m^3.

    So you know the force on each wall is ρAgd/2 assuming the walls can sustain max pressure of twice average pressure without breaking apart.

    1 tonne = 1000kg*g of force. (It is not a measure of pressure but of force.)

    The rest is 1st year high school algebra.
     
  4. Jan 13, 2013 #3
    That's exactly what I did:

    Here's how I done:

    F on each wall= (1766KN)

    1T/m^2 = 9800 pa
    5T/m^2 = 49000 pa

    Force exerted by the hydraulic ram on the wall = 49000 X ( Depth x width ) = 882 KN for each Hydraulic ram.

    So, to resist an opposite force of 1766KN I will need 2 Hydraulic rams.


    Is this right ? thanks
     
  5. Jan 13, 2013 #4

    rude man

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    The force on two of your walls is greater than that on the other two since your room is not square-shaped.
     
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