How Many Oscillations to Reduce Amplitude by 1000 in a Damped System?

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SUMMARY

The discussion centers on calculating the minimum number of oscillations required for a damped mass-spring system to reduce its amplitude by a factor of 1000. The system parameters include a damping constant of 1.00 Ns/m, a spring constant of 1.00 N/m, and a mass of 1.00 kg. The solution involves using the equation x(t) = A e^(-bt/2m) and applying logarithmic properties to determine that the answer is two oscillations. The key insight is transforming the exponential decay into a logarithmic form to solve for the time variable.

PREREQUISITES
  • Understanding of damped harmonic motion
  • Familiarity with the mass-spring system equations
  • Knowledge of natural logarithms and their properties
  • Basic calculus concepts related to exponential functions
NEXT STEPS
  • Study the derivation of the damped harmonic motion equations
  • Learn about the effects of varying damping constants on oscillation amplitude
  • Explore the relationship between logarithmic functions and exponential decay
  • Investigate real-world applications of damped systems in engineering
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to enhance their understanding of damped systems.

frostking
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Homework Statement


A mass spring system has the following parameters: damping constant is 1.00 Ns/m spring constant is 1.00N/m and mass is 1.00 kg The mass is displaced from equilibrium and released. Through what minimum number of oscillations must the mass move in order to reduce the initial amplitude by a factor of 1000 or more?


Homework Equations


x(t) = A e ^(-bt/2m) angular accel W = (k/m - b^2/4m^2)^(1/2) T = 2pi/w


The Attempt at a Solution



I computed w and got 0.86 I know that e ^(-bt/2m) is equal to or less than 1/1000 But this is where I get stuck. Some number times w needs to be less than 1/1000 the original amplitude but...I cannot see how to get there. I know from the solution sheet that the answer is two but can someone please show me how to get there? Thanks, Frostking
 
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frostking, I'm the retired high school teacher here to give a helping hand when I can. It looks like you've got an exponential that needs to be inverted into a log. When you have e^x = .001, you can take the natural log of both sides to get x = ln(.001). I hope that will be useful!
 

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