How Many Oscillators in a Carbon Nanoparticle with 5000 Atoms?

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Homework Help Overview

The discussion revolves around determining the number of oscillators in a carbon nanoparticle containing 5000 carbon atoms, based on the Einstein model of solids. Participants express uncertainty about how to approach the problem, particularly in the context of upcoming exams.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Some participants question how to begin solving the problem, while others mention using a multiplication method related to the number of atoms. There are references to formulas and previous discussions that may influence their reasoning.

Discussion Status

The conversation reflects a mix of attempts to understand the problem and share insights. While some participants offer potential methods, there is no clear consensus or resolution yet. The discussion remains open-ended with various interpretations being explored.

Contextual Notes

Participants note the pressure of having homework due before an exam, which may affect their ability to focus on the problem at hand. There are indications of shared stress regarding the exam and the relevance of the homework content.

yoyoz41
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Homework Statement



A carbon nanoparticle (very small particle) contains 5000 carbon atoms. According to the Einstein model of a solid, how many oscillators are in this block?


I didn't know how to start, can anyone give me a suggesstion??
 
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lol i posted this below with the exact same heading. i have NO idea, but if i figure it out i will let you know
what's up with having homework the night before the exam and this stuff is not even on it :(
 
haha terrible
trying to study and doing homework at same time
omg... exam... and recitation... tmr
 
hey for this i just multiplied by 3 to get the answer.
the question below asking for number of atoms you / by 3
good luck on the exam tomorrow!
 
omg u are my hero
thx a lot
 
haha no problem
did you happen to get the last question with the asteroid??
or part (b) of question 6?
those are the only 2 i don't have?
 
not yet
I am still trying haha
 
yoyoz41 said:
not yet
I am still trying haha

i used the formula on the link that you gave me and it worked for me. might have just been luck but oh well lol
 
haha, maybe, caz the person who anwer it also with no explanation
 

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