How Many Photoelectrons Are Ejected Per Second in This Experiment?

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The discussion focuses on calculating the number of photoelectrons ejected per second in a specific experiment, as represented by a provided graph. The user has shared a link to the graph and mentioned their calculations, noting that the maximum kinetic energy (K[max]) is 10 eV. They express confusion over their results, indicating that their answer is significantly off. The user also clarifies that to find the number of photoelectrons, one must divide the maximum current by the charge of a single electron (1.60E-19 C). Assistance is requested to resolve the discrepancies in their calculations.
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1. To make it easier I just scanned it

http://farm3.static.flickr.com/2062/2457086181_c2a13b6077_o.jpg"


I am supposed to find how many photoelectrons are ejected per second in the experiment represented by the graph.

2. See link



3. Also see link, all of my work so far is there [not all of it, my tutor took other figurings with her, so excuse the lack of lots of writing], I figured since Kinetic energy and potential difference were directly proportional K[max] is 10eV, but as you can see my answer is way off, anyway, any help would be greatly appreciated, and yes, I am female, I write in pink =D.
 
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Nm, you just have to divide max current since it's C/s by 1.60E-19 C.
 
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