SUMMARY
The discussion focuses on calculating the number of photons emitted per second by a blue laser with a power output of 800 milliwatts (0.8 watts) and a photon energy of 3.1 eV. The correct approach involves using the equation E = hv, where h is Planck's constant (6.626e-34 J·s), and converting the power from watts to electronvolts per second using the conversion factor 1 Ws = 6.24151e18 eV. The final calculation reveals that the laser emits approximately 1.5479e19 photons per second.
PREREQUISITES
- Understanding of photon energy and the relationship between energy and frequency (E = hv).
- Familiarity with unit conversions, specifically between joules and electronvolts.
- Basic knowledge of laser physics and power output measurements.
- Ability to manipulate scientific notation and perform calculations with large numbers.
NEXT STEPS
- Study the principles of laser operation and photon emission.
- Learn about Planck's constant and its applications in quantum mechanics.
- Explore unit conversion techniques, particularly between joules and electronvolts.
- Investigate the implications of photon energy in various applications, such as photonics and semiconductor physics.
USEFUL FOR
Students in physics, particularly those studying optics and quantum mechanics, as well as professionals in the fields of photonics and laser technology.