1. The problem statement, all variables and given/known data An electron in the 3rd stationary state around a hydrogen atom has an energy value of -1.512 eV. What will the electron's energy be if the hydrogen atom absorbs a photon with a wavelength of 1090 nm? E = -1.512 eV 2. Relevant equations Ephoton = hc/λ 3. The attempt at a solution I'm unsure if my formula was the correct one to use... E photon = hc/λ = (6.63 x 10^-34 J*s)(3.00 x 10^8 m/s) / (1090 x 10^-9 m) = 1.82477064 x 10^-19 J = 1.140481651 eV ΔE = Ef - Ei Ef = ΔE + Ei = (1.140481651 eV) + (-1.512 eV) = -0.371518349 eV The electron's energy will be about -0.3715 eV I am really just unsure of my process and therefore my answer, so I would just like a second opinion. Thank you!