How Many Radioactive Atoms Are in a 6GBq Sample of 99mTc and What Is Its Mass

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SUMMARY

The discussion focuses on calculating the number of radioactive atoms in a 6GBq sample of 99mTc and determining its mass. Using the decay constant (λ) derived from the half-life of 6 hours, the number of nuclei (N) is calculated as 5.21 × 1017. The mass of the sample is subsequently computed to be approximately 8.18 × 10-7 kg, utilizing Avogadro's number (6.023 × 1023) and the mass number of 99mTc.

PREREQUISITES
  • Understanding of radioactive decay and half-life calculations
  • Familiarity with the decay constant (λ) and its derivation
  • Knowledge of Avogadro's number and its application in mass calculations
  • Basic proficiency in manipulating scientific notation
NEXT STEPS
  • Study radioactive decay equations and their applications in nuclear chemistry
  • Learn about the properties and applications of 99mTc in medical imaging
  • Explore advanced calculations involving decay constants and half-lives
  • Investigate the implications of radioactive mass calculations in practical scenarios
USEFUL FOR

This discussion is beneficial for students in nuclear chemistry, medical physics professionals, and anyone involved in the calculation of radioactive materials in scientific research or medical applications.

Millano
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Homework Statement



How many radioactive atoms are present in a sample of 6GBq of 99mTc and what is the approximate mass of the sample?

Homework Equations



A= λN
half life = ln2/λ
mass = (no.nuclei * mass number)/avorgado number
avogado = 6.023×10^23
half life = 6 hours

The Attempt at a Solution



worked out λ using the above half life (6 hours) and then N (no. nuclei). My problem is that we was not given the half life to beign with. Is there any other way of working it out without the half life ?
 
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N = 6GBq / λ λ= ln2 / half life λ = 0.693 / 6 λ = 0.115N = 6 GBq / 0.115N = 5.21 × 10^17mass = (no. nuclei * mass number) / avogado number mass = (5.21 × 10^17 * 99) / 6.023×10^23mass = 8.18 × 10^-7 kg
 

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