How Many Revolutions Does a Car Make From Rest to a Specific Acceleration?

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SUMMARY

A car starting from rest on a curve with a radius of 110 m and accelerating at 1.20 m/s² will reach a total acceleration of 2.20 m/s² after a certain number of revolutions. The total acceleration is the vector sum of tangential and centripetal acceleration. To determine the number of revolutions, one must calculate the centripetal acceleration using the formula Ac = v²/r and then apply kinematic equations to find the time and distance traveled. This approach leads to the final calculation of the angle and the number of revolutions completed.

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# of Revolutions made

I had the same question as someone else here, but they figured it out but nothing was said in the post. As such, I was asked to make a new thread..
So, pretty much, I have this question:

1. Homework Statement
A car starts from rest on a curve with a radius of 110 m and accelerates at 1.20 m/s^2. How many revolutions will the car have gone through when the magnitude of its total acceleration is 2.20 m/s^2?


2. Homework Equations

theta (final)=theta (initial)+omega*(delta)t+(a*(delta)t^2)/2*r

3. The Attempt at a Solution

i just have no idea how to figure out the time or the distance (or the angle) it takes the car to get from one acceleration to another...
 
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Total acceleration = vector sum of tangential acceleration and centripetal acceleration.
Solve for centripetal acceleration.

Ac = v^2/r
Solve for v.

Use a kinematic equation with v, you should be done.
 

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