SUMMARY
A 66.0-cm-diameter cyclotron accelerates protons using a 530 V oscillating potential difference. The cyclotron frequency is calculated as f = 1.1 x 107 revolutions per second using the formula f = (q*B)/(2*pi*m). To determine the number of revolutions before the proton exits, one must calculate the proton's speed at the cyclotron's radius and its kinetic energy, considering that each revolution adds 2*530 eV to its energy. The conversion from electronvolts to joules is essential for accurate calculations.
PREREQUISITES
- Understanding of cyclotron physics and operation
- Familiarity with the concepts of electric potential and kinetic energy
- Knowledge of the relationship between frequency, charge, magnetic field, and mass
- Ability to convert energy units from electronvolts to joules
NEXT STEPS
- Calculate the proton's speed at the radius of the cyclotron using v = r * f
- Determine the total kinetic energy of the proton upon exiting the cyclotron
- Explore the implications of varying the potential difference on proton acceleration
- Investigate the effects of magnetic field strength on cyclotron frequency
USEFUL FOR
Physics students, educators, and professionals interested in particle acceleration and cyclotron design.