Energy inside a cyclotron, and the frequency of circular motion

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SUMMARY

The discussion focuses on calculating the maximal energy of protons accelerated by a cyclotron with a diameter of 28 cm and a magnetic field strength of 1.4 T. The kinetic energy (Ek) is calculated using the formula Ek = (q²B²R²)/2m, yielding a result of 1.1786 x 10-12 J. Additionally, the frequency of circular motion is determined using ω = qB/m, resulting in 1.34059 x 108 rad/s. The participants clarify that the radius used in calculations should be half of the diameter, confirming the correct approach to the problem.

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  • Familiarity with electromagnetic theory
  • Knowledge of kinetic energy equations
  • Basic calculus for angular frequency calculations
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Students in physics, engineers designing particle accelerators, and researchers in nuclear physics will benefit from this discussion, particularly those focused on the principles of cyclotron mechanics and energy calculations.

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Homework Statement


One of the first cyclotrons, built in 1932, has D-s with a diameter of 28 cm, and its magnet was capable of producing magnetic field of 1.4 T. What is the maximal energy of the protons accelerated by this cyclotron? What is the frequency of the circular motion?

Homework Equations


A) Ek = (q2B2R2)/2m
B) ω = V / r, or qB / m

The Attempt at a Solution


A) ((1.602 X 10-19)2 X 1.42T X 0.282m)/(2 X 1.673 X 10-27kg) = 1.1786 X 10-12 J

B) (1.602 X 10-19 X 1.4T) / 1.673 X 10-27kg = 1.34059 X 108 rad/s

That make sense to your guys?
 
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Shouldn't the radius be half of the diameter?
 
gneill said:
Shouldn't the radius be half of the diameter?

Oh you're right! Read the problem too fast there!
 

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