# How Many Revolutions Does the Smaller Disk Make Around the Larger Circle?

• pchalla90
In summary, the conversation discusses two disks of uniform density that touch at one point and have masses in a ratio of 1:9. The smaller disk makes one rotation around the big circle and it is assumed that the disks do not slip. By using the formula M(a)/R^2(a)=M(b)/R^2(b), it is determined that the smaller disk makes three rotations around the big circle. However, it is noted that the point of contact between the two disks also makes one revolution, so the total number of revolutions for the smaller disk is four. This is similar to the concept of the Earth's revolution around the sun, where the Earth's rotation must be added to the number of revolutions it makes around the sun
pchalla90
There are two disks of uniform density that touch at one point. their masses are in a ratio of 1:9. how many revolutions does the smaller disk make as it makes one rotation around the big circle? (assume that the disks do not slip)

This is my try:

a is small circle
b is big circle

M(a)/R^2(a)=M(b)/R^2(b)

M(a)R^2(b)=M(b)R^2(a)

M(a)R^2(b)=9M(a)R^2(a)

R^2(b)=9R^2(a)

R^2(b)=9

R(b)=3

Circumference of B

2(pi)(3)=6pi

Circumference of A

2(pi)(1)=2pi

number of rotations a makes around b

6pi/2pi=3

so three rotations.

help.

pchalla90 said:

help.

Looks right to me.

When the little disk has gone a quarter round, from say 12 o'clock to 3 o'clock on the big disc, the bit that touches changes from 6 o'clock to 9 o'clock. So 9 o'clock is touching 3 o'clock, which means that the little disc has gone round exactly once!

Either you're right or I'm as dumb as you are!

help.

tiny-tim said:
When the little disk has gone a quarter round [of the big disk]...the little disc has gone round exactly once!

that's the logic. in one quarter of the big disk, the little disk has made one revolution. so in another quarter, it will go again only once. catch my drift?

four quarters

four revolutions...

now to the math part of that...

tiny-tim said:
Either you're right or I'm as dumb as you are!

by the way, this shows that you're smarter than i am, so none of your options

… perhaps I'm just sleepier than you are! …

oops! I wrote my last post just before going to bed, and I think I mis-read your original post.

When you wrote "the answer is four", I thought you meant your answer was 4, and that you'd added the 1 (see below) to the 3 to get 4.

But after a good night's sleep I see you meant your answer was 3 and the official answer was 4.

mmm …

It would have been better if I'd said that the math is that you'd correctly worked out how many revolutions it made relative to the point of contact, but you had to add on the number of revolutions of the point of contact itself (which is 1)!

It's like the question: how many times does the Earth revolve in one year? The answer is 366ish, not 365ish, because you have to add on one extra turn for its orbit round the sun.

tiny-tim said:
you had to add on the number of revolutions of the point of contact itself (which is 1)!

can you explain that more?

are you saying that the point that is touching both circles when we start is the "point of contact"?

so i calculated how many times that point of contact on the small circle touches the big circle?

Point of contact

pchalla90 said:
are you saying that the point that is touching both circles when we start is the "point of contact"?

No

The "point of contact" is moving round both circles. At any particular time, it's the point on each circle that just happens to be touching the other circle at that particular time.

Imagine that the centres of both circles are fixed, and that both circles are free to rotate (like a pair of cogwheels).

Then obviously the little circle goes round three time while the big circle goes round once.

Now glue the circles together, and rotate both of them once around the centre of the big circle.

You've now achieved the same as in the original exercise, except that instead of the little circle gradually going round the big one, it did all its "own" turning first, and then whizzed round the big circle all in one go!

And that's why you always have to add one!

(btw, the Earth's year is 365ish "solar days", but 366ish "sidereal days" - a sidereal day is the time it takes a star to "go round the Earth".)

thanks!

## What is the relationship between two circles and revolutions?

The relationship between two circles and revolutions is that the circumference of a circle is equal to the distance traveled by a point on the circle as it completes one revolution around its center. Therefore, the number of revolutions can be calculated by dividing the distance traveled by the circumference of the circle.

## How do you calculate the circumference of a circle?

The circumference of a circle can be calculated using the formula C = 2πr, where C is the circumference, π is approximately 3.14, and r is the radius of the circle.

## What is the difference between linear and circular motion?

The main difference between linear and circular motion is the shape of the path followed by an object. In linear motion, the object moves along a straight line, while in circular motion, the object moves along a circular path.

## Why is the concept of revolutions important in physics?

The concept of revolutions is important in physics because it helps us understand and analyze the motion of objects in circular paths. It also provides a way to measure rotational motion and calculate important quantities such as angular velocity and acceleration.

## How does the radius of a circle affect the number of revolutions?

The radius of a circle directly affects the number of revolutions. As the radius increases, the circumference also increases, resulting in a longer distance traveled for one revolution. Therefore, the number of revolutions decreases as the radius increases and vice versa.

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