How many solutions are there in Z2?

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Homework Help Overview

The problem involves finding all solutions to a system of equations in the binary field Z2. The equations presented are linear and include variables x1, x2, x3, x4, and x5, with the goal of determining the total number of solutions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the system as nonhomogeneous and the implications of having a constant term on the right-hand side of the equations. There is an exploration of the augmented matrix representation and the reduction process. Questions arise regarding the results of the row reduction and the interpretation of the equations obtained.

Discussion Status

Some participants have provided guidance on the nature of the system and the expected form of the equations after reduction. There is an ongoing exploration of the implications of the reduced equations and how to enumerate possible solutions based on variable combinations.

Contextual Notes

Participants note the importance of working within the constraints of Z2, where certain operations may yield different results compared to standard arithmetic. There is also mention of the need to evaluate combinations of specific variables to find all solutions.

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Homework Statement



In Z2 find all solutions to

x1 + x3 + x4 = 1
x1 +x2 +x4 +x5 =1
x1 + x5 = 1.

How many solutions in total are there?

The Attempt at a Solution



I attempted to reduce row it however I'd be left with a "1" on the right hand side. Its not hard but I am hitting some sort of block!
 
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The presence of a 1 on the RHS isn't a problem. You're trying to solve an inhomogeneous system, so a constant term in the solution is expected.

What equations did you get after you reduced them?
 
Since this is a nonhomogeneous system (as vela points out), you should be working with an augmented matrix with 3 rows and 6 columns. The sixth column will have the constants.
 
vela said:
The presence of a 1 on the RHS isn't a problem. You're trying to solve an inhomogeneous system, so a constant term in the solution is expected.

What equations did you get after you reduced them?

Mark44 said:
Since this is a nonhomogeneous system (as vela points out), you should be working with an augmented matrix with 3 rows and 6 columns. The sixth column will have the constants.

Okay, after I reduced this is what I got:

1 0 0 0 1 1
0 1 0 1 0 0
0 0 1 1 -1 0

so,

x3 = x5 - x4
x2 = - x4
x1 = - 1 - x5

??
 
It should be x1 = 1 - x5, but in Z2, it doesn't really matter.

Now just enumerate all possible combinations for x4 and x5 and evaluate the equations for each combination to find all the solutions to the system.
 

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