How many stars in our galaxy if they had the mass of our Sun.

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Homework Help Overview

The problem involves estimating the mass of the Milky Way Galaxy based on the Sun's orbit and the assumption that all stars have the same mass as the Sun. The original poster expresses uncertainty about how to begin the calculations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using gravitational equations and orbital mechanics to estimate the galaxy's mass. There is a suggestion to treat the galaxy as a planet around which the Sun orbits. Some participants question the completeness of the equations being used.

Discussion Status

Participants are actively engaging with the problem, with some providing calculations and others clarifying concepts. There is a recognition of the small value obtained in one calculation, but no consensus on the correctness of the approach or results has been reached.

Contextual Notes

The original poster has indicated a lack of clarity on how to start the problem, and there may be assumptions regarding the mass distribution of the galaxy that are being discussed.

balletgirl
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Homework Statement



The Sun rotates about the center of the Milky Way Galaxy at a distance of about 3.00x10^4 light years from the center (1ly= 9.50x10^5 m). If it takes about 200 million years to make one rotation, estimate the mass of our galaxy. Assume the mass distribution of our galaxy is concentrated mostly in a central uniform sphere. If all the stars had about the same mass as our Sun, how many stars would there be in our galaxy?


Homework Equations



I have no clue, the most common equation I use is g=GM/r^2 and a=v^2/r.

The Attempt at a Solution



I do not know where to start.
 
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Treat the galaxy as if it was a planet that the sun was orbiting.
 
Well, g is just gravitational acceleration, and is the a in a=v^2/r... but there's an equation missing.


a=\frac{4 \pi^2 r}{T^2}
 
Okay, so I did T= 200,000,000 yrs = 6.31x10^15 s
& R= 2.85x10^20

a=4pi^2*r/T^2
a= 4(3.14)^2*(2.85x10^20)/(6.31x10^15s)
a=39.4(2.85x10^20)/3.98x10^31
a= 2.81x10^-10

I doubt this is right since it is negative
 
No it's not... the exponent is negative, but the number is positive, just very small. And it should be small...
 

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