- #1
- 28
- 0
The probability, I was taught, for red to appear at roulette (on a European table, with a single green zero) is 18/37; and the probability for non-red to appear (black or green zero) is 19/37. If we live in a deterministic universe (I appreciate that that’s a big if for some, not so much for others) is the actual probabilites for any given spin one and zero (1 and zero) e.g, if it’s been determined that red 36 will appear then it’s 100% guaranteed that red 36 will appear (and 100% guaranteed that non-red will appear. So, in that situation, is the probability for red 1, and the probability of non-red 0?
P.s. I appreciate that, unless you were Laplace’s demon, you couldn’t know this in advance of the spin but I’m still wonderin if, even though we would describe the probabilites as 18/37 and 19/37, they would actually be 1 and 0.
P.s. I appreciate that, unless you were Laplace’s demon, you couldn’t know this in advance of the spin but I’m still wonderin if, even though we would describe the probabilites as 18/37 and 19/37, they would actually be 1 and 0.