How much does a string stretch when under load?

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SUMMARY

The discussion focuses on calculating the elongation of a 12-inch string made of a material with a modulus of elasticity of 10 GPa when subjected to a 100 g load. The initial length of the string is 12 inches (0.305 m), and the cross-sectional area is calculated to be approximately 1.96 x 10^-7 m². The correct formula for the spring constant (k) is derived from k = (EA)/L, where E is the modulus of elasticity, A is the cross-sectional area, and L is the initial length. The final length of the string under load can be determined using the equation F = (EA/L_initial)(L_final - L_initial).

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hm8
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Homework Statement


A 12 inch long string with a 0.5 mm diameter and is composed of a 10GPa modulus
material is fixed at one end and loaded by a 100 g mass at its other end. What is the length
of the string when it is under load? (Note that the length is necessarily greater than 12
inches.)

LInitial = 12 in = .305 m
A = ∏r2 = ∏(.00025)2 = 1.96 * 10-7 m^2
E = 10 N/m2
F= .1 * 9.8 = .98 N


Homework Equations



F=kx

k=(EA)/L


The Attempt at a Solution



Basically I'm just not sure which length to use for finding the spring constant k, the final or initial length?

So should be solving something like this for final length?

F=(EA/Lfinal)(Lfinal-LInitial)

or this:

F=(EA/Linitial)(Lfinal-LInitial)
 
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hm8 said:

F=(EA/Linitial)(Lfinal-LInitial)
Use this one. But first correct your value for E you are way off in the number of zeroes after the '10'.
 

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