How Much Energy is Required to Double the Kinetic Energy of Iron Atoms in a Rod?

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SUMMARY

The discussion focuses on calculating the thermal energy required to double the average kinetic energy of iron atoms in a 500g iron rod at an initial temperature of 25 degrees Celsius. The formula used is EH = mcΔT, where EH is the thermal energy, m is the mass in kilograms, and c is the specific heat capacity of iron (452 J/kg·°C). The correct calculation reveals that the required energy is 6.73 x 104 J, significantly higher than the initially calculated 56.5 J, indicating a misunderstanding of the relationship between temperature change and kinetic energy.

PREREQUISITES
  • Understanding of specific heat capacity and its units (J/kg·°C).
  • Basic knowledge of thermodynamics and kinetic energy concepts.
  • Ability to convert mass from grams to kilograms.
  • Familiarity with the formula EH = mcΔT for thermal energy calculations.
NEXT STEPS
  • Study the relationship between temperature and kinetic energy in thermodynamics.
  • Learn about the specific heat capacities of different materials, focusing on metals.
  • Explore advanced thermal energy calculations involving phase changes and heat transfer.
  • Investigate the implications of thermal energy changes on material properties and behavior.
USEFUL FOR

Students in physics or engineering, educators teaching thermodynamics, and anyone interested in understanding thermal energy calculations related to materials.

roxxyroxx
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Thermal energy question??

Homework Statement


a 500g iron rod has a temp. of 25 degrees C. how much thermal energy must be added to the rod to double the average kinetic energy of the iron atoms?


Homework Equations


EH = mc[tex]\Delta[/tex]T


The Attempt at a Solution


EH = (0.005 kg)(452 J/kg x [tex]\circ[/tex]C)
= 56.5 J
but the answer should be 6.73 x 104
help?
 
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roxxyroxx said:

Homework Statement


a 500g iron rod has a temp. of 25 degrees C. how much thermal energy must be added to the rod to double the average kinetic energy of the iron atoms?


Homework Equations


EH = mc[tex]\Delta[/tex]T


The Attempt at a Solution


EH = (0.005 kg)(452 J/kg x [tex]\circ[/tex]C)
= 56.5 J
but the answer should be 6.73 x 104
help?
You have to show your work completely. '

First of all, how many kg does 500 grams represent?

What temperature does the iron have to reach in order to double its kinetic energy?

AM
 

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