How Much Energy Was Released in the Fuel Tank Explosion?

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SUMMARY

The discussion centers on calculating the energy released during a fuel tank explosion, which resulted in two fragments weighing 20kg and 15kg, propelled to heights of 6.6m and 7.3m, respectively. The potential energy (PE) of each fragment is calculated using the formula PE = mgh, where 'm' is mass, 'g' is gravitational acceleration (9.81 m/s²), and 'h' is height. The total energy released by the explosion is equal to the sum of the potential energies of both fragments, confirming that the energy released converts entirely into kinetic energy (KE) at the moment of the explosion.

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StephenDoty
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A fuel tank explodes, ripping the
container into two pieces of masses 20kg and
and 15kg sending them 6.6m and 7.30000019m high,
respectively. What was the energy released by the
explosion if all energy becomes the KE of the
fragments?

Shouldn't the sum of the PE of both fragments equal the energy released?

PE=mgh=(20kg)*(9.81m/s/s)*(6.6m)
+
PE=mgh=(15kg)*(9.81m/s/s)*(7.30000019m)


Thank you
Stephen
 
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StephenDoty said:
Shouldn't the sum of the PE of both fragments equal the energy released?
If they go straight up, yes. (So you can assume that at their highest point they have only potential energy, but no kinetic energy.)
 

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