Calculating Total Kinetic Energy After Explosion

Click For Summary
SUMMARY

The discussion focuses on calculating the total kinetic energy of two pieces launched from an explosion, with one piece weighing 15 kg and the other 26 kg. The vertical height of the explosion is 7.3 m, and the horizontal distance is 11.2 m. The initial vertical velocity (Vi(y)) is calculated using the formula Vi(y) = √(2 * 9.81 * -7.3), resulting in 11.96 m/s. To find the total kinetic energy, both vertical and horizontal components of velocity must be considered, as kinetic energy depends on the total speed of the objects.

PREREQUISITES
  • Understanding of kinematics and projectile motion
  • Familiarity with the kinetic energy formula: KE = 1/2(mv²)
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Ability to calculate components of velocity in two dimensions
NEXT STEPS
  • Learn how to calculate horizontal and vertical components of velocity in projectile motion
  • Study the concept of total mechanical energy in a system
  • Explore advanced kinematics problems involving multiple dimensions
  • Investigate the effects of mass and height on kinetic energy calculations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy calculations, as well as educators teaching kinematics and projectile motion concepts.

Grogerian
Messages
36
Reaction score
0

Homework Statement


Find the total kinetic energy in the system. a explosion fires two pieces both 7.3m high and 11.2m horizontally total kinetic energy done by the explosion the first piece is 15kg, the second 26kg?


Homework Equations


kinematics
Ke=1/2(mv2)


The Attempt at a Solution


I found that Vi(y) = [tex]\sqrt{2(9.81)(-7.3)}[/tex] = 11.96 m/s do i just use this to find the total energy done? or do i need to consider the x-dir as well, If so how do i do that?
 
Physics news on Phys.org
Grogerian said:

Homework Statement


Find the total kinetic energy in the system. a explosion fires two pieces both 7.3m high and 11.2m horizontally total kinetic energy done by the explosion the first piece is 15kg, the second 26kg?

I found that Vi(y) = [tex]\sqrt{2(9.81)(-7.3)}[/tex] = 11.96 m/s do i just use this to find the total energy done? or do i need to consider the x-dir as well, If so how do i do that?

Hi Grogerian!

The KE depends on the total speed, as you know, so Vy is obviously not enough unless Vx is zero.

(but I can't help any furher, as I don't understand the question. :redface:)
 
Grogerian said:

Homework Statement


Find the total kinetic energy in the system. a explosion fires two pieces both 7.3m high and 11.2m horizontally total kinetic energy done by the explosion the first piece is 15kg, the second 26kg?


Homework Equations


kinematics
Ke=1/2(mv2)


The Attempt at a Solution


I found that Vi(y) = [tex]\sqrt{2(9.81)(-7.3)}[/tex] = 11.96 m/s do i just use this to find the total energy done? or do i need to consider the x-dir as well, If so how do i do that?

Velocity is the sum of the components, so yes, you do need to determine the x component.

Since you can figure the time to drop 7.3m from the peak and you know that will be half the time of its flight, and you know that is 7.3m = 1/2 g*t2. Now you can figure how fast it was to go 11.3m.
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 54 ·
2
Replies
54
Views
11K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K