A 20.0–kg particle is shot horizontally with an initial speed v0 = 10 m/s at a height of
100 m above the ground level (see figure). The particle explodes into identical fragments
when its velocity makes an angle of 35° below the horizontal. Immediately after the
explosion, one fragment moves down vertically; while the other fragment moves initially
horizontally. (Neglect the effect of gravitational force during the explosion).
a) How much energy is released in the explosion?
b) At what times will the two fragments reach the ground?
The Attempt at a Solution
I didn't reach to the answers yet ,, i just got Vy at angle (35) and it's Vy=7 m/s and i dont know what else to do ,, any ideas ??
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