How much kinetic energy is released

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Homework Help Overview

The problem involves a 6.0-kg object that explodes into three segments of equal mass, with two segments moving at 20 m/s at an angle of 60° to each other. The focus is on calculating the kinetic energy released during the explosion.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the kinetic energy released but initially arrives at an incorrect value. They express uncertainty about their calculations and seek assistance. Other participants suggest strategies for simplifying the problem, such as adjusting the coordinate system to minimize errors.

Discussion Status

The discussion has seen some progress, with the original poster acknowledging a mistake in their calculations. Guidance has been offered regarding the placement of the coordinate axes to aid in the analysis, indicating a productive exchange of ideas.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is also a mention of a potential algebraic mistake that could affect the calculations.

gijungkim
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Homework Statement


A 6.0-kg object, initially at rest in free space, “explodes” into three segments of equal mass. Two of these segments are observed to be moving with equal speeds of 20 m/s with an angle of 60° between their directions of motion. How much kinetic energy is released in this explosion?

a.2.4 kJ

b.2.9 kJ

c.2.0 kJ

d.3.4 kJ

e.1.2 kJ

Homework Equations


m1v1 + m2v2 + m3v3 = m1v1f + m2v2f + m3v3f
K = 0.5*m*v^2

The Attempt at a Solution


The answer is c, 2000J, but I got 1500J and I don't know where I did wrong. Can anyone help me?
My work is in the picture
 

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Nevermind I got it. Just made an algebric mistake..
 

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Even so, herer's a tip: place the x-axis halfway between m1 and m2. That way py cancels. Less chance of error. But you do need cos(60) which at first you had 0 :smile: !
 
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BvU said:
Even so, herer's a tip: place the x-axis halfway between m1 and m2. That way py cancels. Less chance of error. But you do need cos(60) which at first you had 0 :smile: !
Thanks for the tip!
 

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