A 6.0-kg object, initially at rest in free space, “explodes” into three segments of equal mass. Two of these segments are observed to be moving with equal speeds of 20 m/s with an angle of 60° between their directions of motion. How much kinetic energy is released in this explosion?
m1v1 + m2v2 + m3v3 = m1v1f + m2v2f + m3v3f
K = 0.5*m*v^2
The Attempt at a Solution
The answer is c, 2000J, but I got 1500J and I don't know where I did wrong. Can anyone help me?
My work is in the picture