How Much Force Is Exerted on the Floor When Pushing a Box?

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SUMMARY

The discussion centers on calculating the force exerted on the floor when pushing a 25 kg box at a constant speed, with a coefficient of kinetic friction (μk) of 0.20. The frictional force (Ff) is determined using the formula Ff = μk * Fn, where Fn is the normal force. Given that the normal force equals the weight of the box (Fn = mass * gravity), the calculation yields a frictional force of 5 N. The confusion arises from differentiating between the force exerted on the box and the force exerted on the floor.

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  • Ability to calculate normal force using mass and gravitational acceleration
  • Familiarity with basic algebra for solving equations
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Homework Statement


you push a 25 kg box across a wooden floor at constant speed. how much force do you exert on the floor? (mu(k) = 0.20

Homework Equations



Ff=<uFn

The Attempt at a Solution


this is wat i get so far
mass = 25kg
uk= .20

.20<.20x25
.20<5

is this correct? I am confuse coz of how much force you exert on the floor not on the box?
i need help guys
 
Last edited:
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solve your other question
you'll get this one too
 
hav0c said:
solve your other question
you'll get this one too

what do you mean?
 
What forces does the box exert on the floor?
 
jamesblim168 said:
what do you mean?
your thread "How to calculate force applied?" contains the answer
 

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